REGEN % and accessory loads

[djm74]

I am hoping someone has info/data on what % of the Prius's kinetic energy can be regenerated on average. I know it varies quite a bit based on battery level, grade, etc, but a general idea would be helpful.

I am also looking for data on overall accessory load (kW preferably), and a breakdown would be even better.

Thanks for the help!

[ken1784]

[quote=djm74 @ Nov 10 2006, 08:04 AM) [snapback]346589[/snapback]</div>

I am hoping someone has info/data on what % of the Prius's kinetic energy can be regenerated on average. I know it varies quite a bit based on battery level, grade, etc, but a general idea would be helpful.
[/b]

Attila did an experiment...
http://vassfamily.net/ToyotaPrius/CAN/eveffindex.html

I am also looking for data on overall accessory load (kW preferably), and a breakdown would be even better.
[/b]

My observations of HV battery current numbers are...

Base (metabolism): about 1A] 220V = 0.22 kW
Parking lights: about 0.2 A
HID lamps: about 0.4 A
Fans: about 0.2 - 1.2 A
AC: about 0.5 - 10.0A

Ken@Japan

[hdrygas]

I run 2-3 amps with the light air and radio on.

[donee]

Hi Djm74,

I did some simple analysis on Atila's data. Its detailed in http://www.priusonline.com/viewtopic.php?t...asc&start=0 . The short answer was Attila got 81.5 percent regeneration efficiency ( Energy of regenerated electricity / Energy of Car Motion), and 66.6 percent electric acceleration efficiency (Energy of resulting motion / Energy of electricity applied to motor).

The Efficiency of reuse was then .815 times .666 times battery efficiency (times 100 percent) or 54.3 percent times battery efficiency .

Guidance from this info is that the electric acceleration is not super efficient. Cruise would be more efficient as the motor and inverter losses are approximately a fixed resistance, and lower currents would result in less energy dissipated as heat.

[djm74]

Thanks for the info. The efficiency of reuse must assume there is enough storage space available in the battery to recapture that much energy. The model I am trying to come up with needs a single reuse value, so do you think I should further discount the efficiency to account for this occassional lack of storage space issue? Or is the battery almost never topped off enough to preclude sending the regen energy back to it?

Thanks!!


<div class='quotetop'>QUOTE(donee @ Nov 12 2006, 07:50 AM) [snapback]347768[/snapback]</div>

Hi Djm74,

I did some simple analysis on Atila's data. Its detailed in http://www.priusonline.com/viewtopic.php?t...asc&start=0 . The short answer was Attila got 81.5 percent regeneration efficiency ( Energy of regenerated electricity / Energy of Car Motion), and 66.6 percent electric acceleration efficiency (Energy of resulting motion / Energy of electricity applied to motor).

The Efficiency of reuse was then .815 times .666 times battery efficiency (times 100 percent) or 54.3 percent times battery efficiency .

Guidance from this info is that the electric acceleration is not super efficient. Cruise would be more efficient as the motor and inverter losses are approximately a fixed resistance, and lower currents would result in less energy dissipated as heat.
[/b]

[DanMan32]

<div class='quotetop'>QUOTE(djm74 @ Nov 13 2006, 01:14 AM) [snapback]348067[/snapback]</div>

Thanks for the info. The efficiency of reuse must assume there is enough storage space available in the battery to recapture that much energy. The model I am trying to come up with needs a single reuse value, so do you think I should further discount the efficiency to account for this occassional lack of storage space issue? Or is the battery almost never topped off enough to preclude sending the regen energy back to it?

Thanks!!
[/b]

Well, you can't put 10 gallons in a 5 gallon bucket, so there will be a point where the battery will not be given a charge from regen. Slowing down without regen provides 0% efficiency, so it does sound like you need to factor that in.

Or perhaps I am not understanding your last post.